A) $ -{\log_2}(1-x) $
B) $ -{\log_2}(x) $
C) 0
D) 1
Correct Answer: A
[a] Let $ y=1-{2^{-x}}or{2^{-x}}=1-y $ or $ -x={\log_2}(1-y)or{f^{-1}}(x)=g(x)=-log_2(1-x). $
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