Functions Question 76

Question: $ \underset{x\to 3}{\mathop{\lim }},{ \frac{x-3}{\sqrt{x-2}-\sqrt{4-x}} }= $

[MNR 1991]

Options:

A) 1

B) 2

C) ?1

D) ?2

Show Answer

Answer:

Correct Answer: A

Solution:

$ \underset{x\to 3}{\mathop{\lim }}{ \frac{x-3}{\sqrt{x-2}-\sqrt{4-x}} }=\underset{x\to 3}{\mathop{\lim }}\frac{(x-3),{ \sqrt{x-2}+\sqrt{4-x} }}{2,(x-3)}=1 $ . Aliter : Apply L-Hospital?s rule.