Functions Question 76
Question: $ \underset{x\to 3}{\mathop{\lim }},{ \frac{x-3}{\sqrt{x-2}-\sqrt{4-x}} }= $
[MNR 1991]
Options:
A) 1
B) 2
C) ?1
D) ?2
Show Answer
Answer:
Correct Answer: A
Solution:
$ \underset{x\to 3}{\mathop{\lim }}{ \frac{x-3}{\sqrt{x-2}-\sqrt{4-x}} }=\underset{x\to 3}{\mathop{\lim }}\frac{(x-3),{ \sqrt{x-2}+\sqrt{4-x} }}{2,(x-3)}=1 $ . Aliter : Apply L-Hospital?s rule.