Functions Question 80

Question: $ \underset{x\to \infty }{\mathop{\lim }},\frac{(x-1)(2x+3)}{x^{2}}= $

Options:

A) 1

B) ?1

C) 2

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

$ \underset{x\to \infty }{\mathop{\lim }},\frac{(x-1)(2x+3)}{x^{2}}=\underset{x\to \infty }{\mathop{\lim }},\frac{2x^{2}+x-3}{x^{2}}=2. $