Functions Question 80
Question: $ \underset{x\to \infty }{\mathop{\lim }},\frac{(x-1)(2x+3)}{x^{2}}= $
Options:
A) 1
B) ?1
C) 2
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ \underset{x\to \infty }{\mathop{\lim }},\frac{(x-1)(2x+3)}{x^{2}}=\underset{x\to \infty }{\mathop{\lim }},\frac{2x^{2}+x-3}{x^{2}}=2. $