Integral Calculus Question 107
Question: $ \int_{{}}^{{}}{\sqrt{1-\sin 2x}\ }dx=……..,\ \ x\in (0,\ \pi /4) $
[MP PET 1987]
Options:
A) $ -\sin x+\cos x $ + C
B) $ \sin x-\cos x $ + C
C) $ \tan x+\sec x $ + C
D) $ \sin x+\cos x $ + C
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Answer:
Correct Answer: D
Solution:
$ \int_{{}}^{{}}{\sqrt{1-\sin 2x}}dx $ $ =\int_{{}}^{{}}{(\cos x-\sin x)dx=\sin x+\cos x+c.} $
BETA
