Integral Calculus Question 114
Question: If $ \int_{{}}^{{}}{x\sin xdx=-x\cos x+A} $ , then $ A= $
[MP PET 1992, 2000; RPET 1997]
Options:
A) $ \sin x+ $ Constant
B) $ \cos x+ $ Constant
C) Constant
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
Since, $ \int_{{}}^{{}}{x\sin x,dx}=-x\cos x+A $
$ \Rightarrow -x\cos x+\sin x+constant=-x\cos x+A $ Equating it, we get $ A=\sin x+constant\text{.} $
BETA
