Integral Calculus Question 126

Question: $ \int_{{}}^{{}}{x\cos x\ dx=} $

[MP PET 1988]

Options:

A) $ x\sin x+\cos x $

B) $ x\sin x-\cos x $

C) $ x\cos x+\sin x $

D) $ x\cos x-\sin x $

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Answer:

Correct Answer: A

Solution:

$ \int_{{}}^{{}}{x\cos x,dx}=x\sin x-\int_{{}}^{{}}{\sin x,dx+c}=x\sin x+\cos x+c $ .