Integral Calculus Question 126
Question: $ \int_{{}}^{{}}{x\cos x\ dx=} $
[MP PET 1988]
Options:
A) $ x\sin x+\cos x $
B) $ x\sin x-\cos x $
C) $ x\cos x+\sin x $
D) $ x\cos x-\sin x $
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Answer:
Correct Answer: A
Solution:
$ \int_{{}}^{{}}{x\cos x,dx}=x\sin x-\int_{{}}^{{}}{\sin x,dx+c}=x\sin x+\cos x+c $ .