Integral Calculus Question 131
Question: Find the value of $ \int\limits_0^{9}{[\sqrt{x}+2]dx} $ where $ [\cdot ] $ is the greatest integer function:
Options:
A) 31
B) 22
C) 23
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
[a] We have $ \int\limits_0^{9}{[\sqrt{x}+2]dx} $ $ =\int\limits_0^{1}{2dx+\int\limits_1^{4}{3dx+\int\limits_4^{9}{4dx}}} $ $ =2+(12-3)+(36-16)=2+9+20=31 $
BETA
