Integral Calculus Question 134

Question: $ \int_{{}}^{{}}{\frac{\sin x\ dx}{a^{2}+b^{2}{{\cos }^{2}}x}}= $

Options:

A) $ \log (a^{2}+b^{2}{{\cos }^{2}}x)+c $

B) $ \frac{1}{ab}{{\tan }^{-1}}( \frac{a\cos x}{b} )+c $

C) $ \frac{1}{ab}{{\cot }^{-1}}( \frac{b\cos x}{a} )+c $

D) $ \frac{1}{ab}{{\cot }^{-1}}( \frac{a\cos x}{b} )+c $

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Answer:

Correct Answer: C

Solution:

Put $ b\cos x=t $ .