Integral Calculus Question 134
Question: $ \int_{{}}^{{}}{\frac{\sin x\ dx}{a^{2}+b^{2}{{\cos }^{2}}x}}= $
Options:
A) $ \log (a^{2}+b^{2}{{\cos }^{2}}x)+c $
B) $ \frac{1}{ab}{{\tan }^{-1}}( \frac{a\cos x}{b} )+c $
C) $ \frac{1}{ab}{{\cot }^{-1}}( \frac{b\cos x}{a} )+c $
D) $ \frac{1}{ab}{{\cot }^{-1}}( \frac{a\cos x}{b} )+c $
Show Answer
Answer:
Correct Answer: C
Solution:
Put $ b\cos x=t $ .