[Roorkee 1982]
A) $ \log x-\log (1-x)+c $
B) $ \log (1-x^{2})+c $
C) $ -\log x+\log (1-x)+c $
D) $ \log (x-x^{2})+c $
Correct Answer: A
$ \int_{{}}^{{}}{\frac{dx}{(x-x^{2})}=\int_{{}}^{{}}{( \frac{1}{x}+\frac{1}{1-x} )}dx=\log x-\log (1-x)+c} $ .
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