[MP PET 1999]
A) $ \cot x+c $
B) $ -\cot x+c $
C) $ {{\tan }^{2}}x+c $
D) $ -{{\cot }^{2}}x+c $
Correct Answer: B
$ \int_{{}}^{{}}{cose{c^{2}}x,dx}=-\cot x+c $ .
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