Integral Calculus Question 23
Question: $ \int_{{}}^{{}}{\frac{dx}{(x+1)(x+2)}=} $
[MP PET 1987]
Options:
A) $\log \left| \frac{x+2}{x+1}\right|+c$
B) $\log \left| (x+1)\right|+\log \left|(x+2) \right|+c$
C) $\log \left| \frac{x+1}{x+2}\right|+c$
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ \int_{{}}^{{}}{\frac{dx}{(x+1)(x+2)}}=\int_{{}}^{{}}{( \frac{1}{x+1}-\frac{1}{x+2} )},dx $ $ =|\log (x+1)-\log (x+2)|+c=|\log \frac{x+1}{x+2}|+c. $
BETA
