Integral Calculus Question 271
Question: $ \int_{{}}^{{}}{\frac{\sin x+\cos x}{\sqrt{1+\sin 2x}}\ dx=} $
[MP PET 1990]
Options:
A) $ \sin x+c $
B) $ \cos x+c $
C) $ x+c $
D) $ x^{2}+c $
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Answer:
Correct Answer: C
Solution:
$ \int_{{}}^{{}}{\frac{\sin x+\cos x}{\sqrt{1+\sin 2x}},dx}=\int_{{}}^{{}}{\frac{\sin x+\cos x}{\sqrt{{{(\sin x+\cos x)}^{2}}}},dx}=\int_{{}}^{{}}{dx=x+c} $ .
BETA
