Integral Calculus Question 274
Question: $ \int_{{}}^{{}}{(1+2x+3x^{2}+4x^{3}+……)\ dx=} $
Options:
A) $ {{(1+x)}^{-1}}+c $
B) $ {{(1-x)}^{-1}}+c $
C) $ {{(1-x)}^{-1}}-1+c $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ \int_{{}}^{{}}{(1+2x+3x^{2}+4x^{3}+……),dx} $ $ =\int_{{}}^{{}}{{{(1-x)}^{-2}}dx={{(1-x)}^{-1}}+c.} $