Integral Calculus Question 277
Question: $ \int_{{}}^{{}}{\frac{3x^{2}-2\sqrt{x}}{x}}dx= $
[Roorkee 1976]
Options:
A) $ x^{3}-\sqrt{x}+c $
B) $ x^{3}+\sqrt{x}+c $
C) $ x^{3}-2\sqrt{x}+c $
D) $ x^{3}-4\sqrt{x}+c $
Show Answer
Answer:
Correct Answer: D
Solution:
$ \int_{{}}^{{}}{\frac{3x^{3}-2\sqrt{x}}{x},dx}=\int_{{}}^{{}}{3x^{2}dx}-2\int_{{}}^{{}}{{x^{-1/2}}dx}=x^{3}-4\sqrt{x}+c $ .
BETA
