[MP PET 1988]
A) $ {{\cos }^{-1}}x+c $
B) $ {{\sec }^{-1}}x+c $
C) $ {{\cot }^{-1}}x+c $
D) $ {{\tan }^{-1}}x+c $
Correct Answer: B
$ \int_{{}}^{{}}{\frac{1}{x\sqrt{x^{2}-1}},dx={{\sec }^{-1}}x+c} $ (formula).
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