Integral Calculus Question 288
Question: $ \int_{{}}^{{}}{( 2\sin x+\frac{1}{x} )\ dx} $ is equal to
[MP PET 1999]
Options:
A) $ -2\cos x+\log x+c $
B) $ 2\cos x+\log x+c $
C) $ -2\sin x-\frac{1}{x^{2}}+c $
D) $ -2\cos x+\frac{1}{x^{2}}+c $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \int_{{}}^{{}}{( 2\sin x+\frac{1}{x} ),dx=-2\cos x+\log x+c} $ .
BETA
