Integral Calculus Question 300
Question: $ \int_{{}}^{{}}{\frac{\sin x+cosec,x}{\tan x}dx=} $
Options:
A) $ \sin x-cosec,x+c $
B) $ cosec,x-\sin x+c $
C) $ \log \tan x+c $
D) $ \log \cot x+c $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \int_{{}}^{{}}{\frac{\sin x+cosec,x}{\tan x}},dx=\int_{{}}^{{}}{(\cos x+cosec,x\cot x),dx} $ $ =\sin x-cosec,x+c $