Integral Calculus Question 320
Question: The value of $ \int_{{}}^{{}}{\frac{1}{x^{4}}\ dx} $ is
[RPET 1995]
Options:
A) $ \frac{1}{-3x^{3}}+c $
B) $ \frac{1}{3x^{3}}+c $
C) $ \frac{1}{-4x^{3}}+c $
D) $ -\frac{1}{3x^{2}}+c $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \int_{{}}^{{}}{{x^{-4}}dx}=\frac{{x^{-3}}}{-3}+c=-\frac{1}{3x^{3}}+c. $