Integral Calculus Question 320

Question: The value of $ \int_{{}}^{{}}{\frac{1}{x^{4}}\ dx} $ is

[RPET 1995]

Options:

A) $ \frac{1}{-3x^{3}}+c $

B) $ \frac{1}{3x^{3}}+c $

C) $ \frac{1}{-4x^{3}}+c $

D) $ -\frac{1}{3x^{2}}+c $

Show Answer

Answer:

Correct Answer: A

Solution:

$ \int_{{}}^{{}}{{x^{-4}}dx}=\frac{{x^{-3}}}{-3}+c=-\frac{1}{3x^{3}}+c. $