Integral Calculus Question 324
Question: $ \int_{{}}^{{}}{\sec x\ dx=} $
[MP PET 1988, 95; RPET 1996]
Options:
A) $ \log \tan ( \frac{\pi }{8}+\frac{x}{2} )+c $
B) $ -\log (\sec x-\tan x)+c $
C) $ \log (\sec x-\tan x)+c $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ \int_{{}}^{{}}{\sec x,dx}=\log (\sec x+\tan x)+c $ $ =\log ( \frac{1}{\sec x-\tan x} )+c=-\log (\sec x-\tan x)+c $ .
BETA
