Integral Calculus Question 325
Question: $ \int_{{}}^{{}}{\log xdx=} $
[MNR 1979; BIT Ranchi 1992; SCRA 1996]
Options:
A) $ x+x\log x+c $
B) $ x\log x-x+c $
C) $ x^{2}\log x+c $
D) $ \frac{1}{x}\log x+x+c $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \int_{{}}^{{}}{\log x,dx}=x\log x-\int_{{}}^{{}}{x,.,\frac{1}{x},dx+c=x\log x-x+c} $ Note : Students should remember this question as a formula.
BETA
