A) $ \frac{\sin kx}{k}+c $
B) $ \frac{\cos kx}{k}+c $
C) $ \frac{\sin x}{k}+c $
D) $ -\frac{x,\cos kx}{k}+\frac{\sin kx}{k^{2}}+c $
Correct Answer: D
$ I=\int_{{}}^{{}}{x\sin kx,dx}=\frac{-x\cos kx}{k}+\frac{\sin kx}{k^{2}}+c $
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