Integral Calculus Question 382
Question: $ \int{e^{x}(1-\cot x+{{\cot }^{2}}x)dx} $ equals
[MP PET 2002]
Options:
A) $ e^{x}\cot x+c $
B) $ e^{x}\text{cosec }x+c $
C) $ -e^{x}\cot x+c $
D) $ -e^{x}cosec,x+c $
Show Answer
Answer:
Correct Answer: C
Solution:
$ I=\int{e^{x}(1-\cot x+{{\cot }^{2}}x),dx}=\int{e^{x}(-\cot x+cose{c^{2}}x),dx} $ $ =e^{x}(-\cot x)+c $ $ =-e^{x},\cot x+c $ .
BETA
