Integral Calculus Question 393
Question: The value of $ \int{\frac{1}{{{(x-5)}^{2}}}dx} $ is
[Karnataka CET 2001; Pb. CET 2002]
Options:
A) $ \frac{1}{x-5}+c $
B) $ -\frac{1}{x-5}+c $
C) $ \frac{2}{{{( x-5 )}^{3}}}+c $
D) $ -2{{( x-5 )}^{3}}+c $
Show Answer
Answer:
Correct Answer: B
Solution:
$ I=\int{\frac{1}{{{(x-5)}^{2}}}dx} $ $ =\frac{{{(x-5)}^{-2+1}}}{-2+1}+c=\frac{{{(x-5)}^{-1}}}{-1}+c $ $ =-\frac{1}{(x-5)}+c $ .
BETA
