Integral Calculus Question 430
Question: $ \int_{{}}^{{}}{\frac{1}{\sqrt{x}}}\sin \sqrt{x}\ dx= $
[MP PET 1989]
Options:
A) $ -\frac{1}{2}\cos \sqrt{x}+c $
B) $ -2\cos \sqrt{x}+c $
C) $ \frac{1}{2}\cos \sqrt{x}+c $
D) $ 2\cos \sqrt{x}+c $
Show Answer
Answer:
Correct Answer: B
Solution:
Put $ \sqrt{x}=t\Rightarrow \frac{1}{\sqrt{x}},dx=2dt, $ then it reduces to $ 2\int_{{}}^{{}}{\sin t,dt}=-2\cos t+c=-2\cos \sqrt{x}+c. $
BETA
