Integral Calculus Question 48
Question: $ \int_{{}}^{{}}{\frac{dx}{\sqrt{2x-x^{2}}}=} $
[MP PET 1991; Karnataka CET 2002]
Options:
A) $ {{\cos }^{-1}}(x-1)+c $
B) $ {{\sin }^{-1}}(x-1)+c $
C) $ {{\cos }^{-1}}(1+x)+c $
D) $ {{\sin }^{-1}}(1-x)+c $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \int_{{}}^{{}}{\frac{dx}{\sqrt{2x-x^{2}}}}=\int_{{}}^{{}}{\frac{dx}{\sqrt{1-{{(x-1)}^{2}}}}}={{\sin }^{-1}}(x-1)+c. $
BETA
