Integral Calculus Question 482
Question: $ \int{x{e^{x^{2}}}}dx= $
[RPET 2003]
Options:
A) $ -\frac{{e^{x^{2}}}}{2}+c $
B) $ \frac{{e^{x^{2}}}}{2}+c $
C) $ \frac{e^{x}}{2}+c $
D) $ -\frac{e^{x}}{2}+c $
Show Answer
Answer:
Correct Answer: B
Solution:
$ I=\int{x{e^{x^{2}}}dx} $ $ =\frac{1}{2}\int{e^{t}dt=\frac{{e^{x^{2}}}}{2}}+c $ . {Put $ x^{2}=t $
Þ $ 2xdx=dt $ }
BETA
