Integral Calculus Question 59
Question: $ \int{\frac{dx}{x^{2}+4x+13}} $ is equal to
[Kerala (Engg.) 2002]
Options:
A) $ \log (x^{2}+4x+13)+c $
B) $ \frac{1}{3}{{\tan }^{-1}}( \frac{x+2}{3} )+c $
C) $ \log (2x+4)+c $
D) $ \frac{2x+4}{{{(x^{2}+4x+13)}^{2}}}+c $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \int{\frac{dx}{x^{2}+4x+13}=\int{\frac{dx}{{{(x+2)}^{2}}+9}=\frac{1}{3}{{\tan }^{-1}}\frac{(x+2)}{3}+c}} $ .
BETA
