Integral Calculus Question 62
Question: $ \int_{{}}^{{}}{\frac{dx}{x^{2}+2x+2}=} $
[Karnataka CET 2004]
Options:
A) $ {{\sin }^{-1}}(x+1)+c $
B) $ {{\sinh }^{-1}}(x+1)+c $
C) $ {{\tanh }^{-1}}(x+1)+c $
D) $ {{\tan }^{-1}}(x+1)+c $
Show Answer
Answer:
Correct Answer: D
Solution:
$ \int_{{}}^{{}}{\frac{dx}{x^{2}+2x+2}=\int_{{}}^{{}}{\frac{dx}{{{(x+1)}^{2}}+1}={{\tan }^{-1}}(x+1)+c}} $ .
BETA
