Integral Calculus Question 86
Question: $ \int_{{}}^{{}}{x{{\sec }^{2}}x\ dx}= $
[RPET 1996, 2003; MP PET 1987, 97; Pb. CET 2002]
Options:
A) $ \tan x+\log |\cos x|+c $
B) $ \frac{x^{2}}{2}{{\sec }^{2}}x+\log |\cos x|+c $
C) $ x\tan x+\log |\sec x|+c $
D) $ x\tan x+\log |\cos x|+c $
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Answer:
Correct Answer: D
Solution:
$ \int_{{}}^{{}}{x{{\sec }^{2}}x,dx=x\tan x}-\int_{{}}^{{}}{\tan x,dx} $ $ =x\tan x+\log |(\cos x)|+c. $
BETA
