Inverse Trigonometric Functions Question 101
Question: The principal value of $ {{\sin }^{-1}}( -\frac{\sqrt{3}}{2} ) $ is
[Roorkee 1992]
Options:
A) $ \frac{-2\pi }{3} $
B) $ \frac{-\pi }{3} $
C) $ \frac{-2\pi }{3} $
D) $ \frac{5\pi }{3} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ {{\sin }^{-1}}( \frac{-\sqrt{3}}{2} )=-{{\sin }^{-1}}( \frac{\sqrt{3}}{2} )=-\frac{\pi }{3} $ .
BETA
