Inverse Trigonometric Functions Question 116
Question: The formula $ {{\sin }^{-1}}{2x(1-x^{2})}=2si{n^{-1}}x $ is true for all values of x lying in the interval
Options:
A) $ [-1,1] $
B) $ [0,1] $
C) $ [-1,0] $
D) $ [ -1/\sqrt{2},1/\sqrt{2} ] $
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Answer:
Correct Answer: D
$ {{\sin }^{-1}}{2x(1-x^{2})}=2si{n^{-1}}x $ is true $ \forall x\in [ -\frac{1}{\sqrt{2}},\frac{1}{\sqrt{2}} ] $
BETA
