Inverse Trigonometric Functions Question 133

Question: The number of real solutions of the equation $ \sqrt{1+\cos 2x}=\sqrt{2}{{\sin }^{-1}}(sinx),-\pi \le x\le \pi $ is

Options:

A) 0

B) 1

C) 2

D) infinite

Show Answer

Answer:

Correct Answer: C

Here $ | \cos x |={{\sin }^{-1}}(x) $ From the graph, the number of solutions is 2.



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