Inverse Trigonometric Functions Question 133
Question: The number of real solutions of the equation $ \sqrt{1+\cos 2x}=\sqrt{2}{{\sin }^{-1}}(sinx),-\pi \le x\le \pi $ is
Options:
A) 0
B) 1
C) 2
D) infinite
Show Answer
Answer:
Correct Answer: C
Here $ | \cos x |={{\sin }^{-1}}(sinx) $ From the graph, the number of solutions is 2.
BETA
