Inverse Trigonometric Functions Question 140

Question: The function $ f(x)={{\tan }^{-1}}(\sin x+\cos x) $ is an increasing function in

Options:

A) $ ( \frac{\pi }{4},\frac{\pi }{2} ) $

B) $ ( -\frac{\pi }{2},\frac{\pi }{4} ) $

C) $ ( 0,\frac{\pi }{2} ) $

D) $ ( -\frac{\pi }{2},\frac{\pi }{2} ) $

Show Answer

Answer:

Correct Answer: B

$ f’(x)=\frac{1}{1+{{(\sin x+\cos x)}^{2}}}(\cos x-\sin x) $

$ f(x) $ is increasing if $ \cos x-\sin x>0 $

Or $ \cos x>\sin x $ Hence, $ f(x) $ is increasing when $ x\in ( -\frac{\pi }{2},\frac{\pi }{4} ) $