A) $ -\frac{\pi }{6} $
B) $ \frac{5\pi }{6} $
C) $ \frac{\pi }{3} $
D) $ \frac{2\pi }{3} $
Correct Answer: B
$ {{\cot }^{-1}}(-\sqrt{3})=\pi -{{\cot }^{-1}}(\sqrt{3})=\frac{5\pi }{6} $ .
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