Inverse Trigonometric Functions Question 146
Question: The value of $ {{\sin }^{-1}}(\sin 10) $ is
Options:
A) 10
B) $ 10-3\pi $
C) $ 3\pi -10 $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
Since $ 3\pi <10<3\pi +\frac{\pi }{2}\Rightarrow 0<10-3\pi <\frac{\pi }{2} $
$ \Rightarrow \frac{-\pi }{2}<3\pi -10<0 $
$ \Rightarrow {{\sin }^{-1}}{ \sin (3\pi -10) }=3\pi -10 $ .
BETA
