Inverse Trigonometric Functions Question 147
Question: $ 1+{{\cot }^{2}}({{\sin }^{-1}}x)= $
Options:
A) $ \frac{1}{2x} $
B) $ x^{2} $
C) $ \frac{1}{x^{2}} $
D) $ \frac{2}{x} $
Show Answer
Answer:
Correct Answer: C
Solution:
Let $ {{\sin }^{-1}}x=\theta \Rightarrow \sin \theta =x $ Now $ 1+{{\cot }^{2}}\theta =\cos ec^{2}\theta =\frac{1}{x^{2}} $ Hence $ 1+{{\cot }^{2}}({{\sin }^{-1}}x)=\frac{1}{x^{2}} $ .
BETA
