Inverse Trigonometric Functions Question 148
Question: If $ {{\sin }^{-1}}\frac{1}{2}={{\tan }^{-1}}x, $ then x =
Options:
A) $ \sqrt{3} $
B) $ \frac{1}{\sqrt{3}} $
C) $ \frac{1}{\sqrt{2}} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
Given that $ {{\sin }^{-1}}\frac{1}{2}={{\tan }^{-1}}x $
$ \Rightarrow {{\tan }^{-1}}x=\frac{\pi }{6} $
$ \Rightarrow x=\tan 30^{o}=\frac{1}{\sqrt{3}} $ .
BETA
