Inverse Trigonometric Functions Question 159
Question: The principal value of $ {{\sin }^{-1}}( -\frac{1}{2} ) $ is
Options:
A) $ \frac{\pi }{3} $
B) $ \frac{\pi }{6} $
C) $ -\frac{\pi }{3} $
D) $ -\frac{\pi }{6} $
Show Answer
Answer:
Correct Answer: D
Solution:
The principal value of $ {{\sin }^{-1}}( -\frac{1}{2} )={{\sin }^{-1}}\sin (-30^{o}) $
$ =-\frac{\pi }{6} $ .
BETA
