Inverse Trigonometric Functions Question 163
Question: $ {{[ \sin ( {{\tan }^{-1}}\frac{3}{4} ) ]}^{2}}= $
[EAMCET 1983]
Options:
A) $ \frac{3}{5} $
B) $ \frac{5}{3} $
C) $ \frac{9}{25} $
D) $ \frac{25}{9} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ {{[ \sin ( {{\tan }^{-1}}\frac{3}{4} ) ]}^{2}}={{[ \sin ( {{\sin }^{-1}}\frac{3}{5} ) ]}^{2}}={{( \frac{3}{5} )}^{2}}=\frac{9}{25} $ .
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