Inverse Trigonometric Functions Question 168
Question: The value of x which satisfies the equation $ {{\tan }^{-1}}x= $
$ {{\sin }^{-1}}( \frac{3}{\sqrt{10}} ) $ is
[Pb. CET 1999]
Options:
A) 3
B) -3
C) $ \frac{1}{3} $
D) $ -\frac{1}{3} $
Show Answer
Answer:
Correct Answer: A
Solution:
Given, $ {{\tan }^{-1}}x={{\sin }^{-1}}[ \frac{3}{\sqrt{10}} ] $
Therefore $ x=\tan { {{\sin }^{-1}}[ \frac{3}{\sqrt{10}} ] }=\tan {{{\tan }^{-1}}3} $
Therefore x = 3.
BETA
