Inverse Trigonometric Functions Question 171
Question: If $ \theta ={{\sin }^{-1}}[\sin (-600^{o})] $ , then one of the possible value of $ \theta $ is
[Kerala (Engg.) 2002]
Options:
A) $ \frac{\pi }{3} $
B) $ \frac{\pi }{2} $
C) $ \frac{2\pi }{3} $
D) $ \frac{-2\pi }{3} $
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Answer:
Correct Answer: A
Solution:
$ \theta ={{\sin }^{-1}}[\sin (-600^{o})] $
Therefore $ \theta ={{\sin }^{-1}}[-(\sin 240^{o})] $
$ ={{\sin }^{-1}}[-\sin (180^{o}+60^{o})] $
Therefore $ \theta ={{\sin }^{-1}}\sin 60^{o} $
$ ={{\sin }^{-1}}[ \sin ( \frac{\pi }{3} ) ]=\frac{\pi }{3} $ .
BETA
