Inverse Trigonometric Functions Question 176
Question: $ \sin [ \frac{\pi }{2}-{{\sin }^{-1}}( -\frac{\sqrt{3}}{2} ) ]= $
Options:
A) $ \frac{\sqrt{3}}{2} $
B) $ -\frac{\sqrt{3}}{2} $
C) $ \frac{1}{2} $
D) $ -\frac{1}{2} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \sin [ \frac{\pi }{2}-{{\sin }^{-1}}( -\frac{\sqrt{3}}{2} ) ]=\cos {{\sin }^{-1}}( -\frac{\sqrt{3}}{2} ) $
$ =\cos {{\cos }^{-1}}\sqrt{1-\frac{3}{4}}=\frac{1}{2} $ .
BETA
