A) 3
B) $ \frac{2}{3} $
C) $ \frac{1}{3} $
D) $ \frac{1}{\sqrt{10}} $
Correct Answer: C
$ \tan ( 90^{o}-{{\cot }^{-1}}\frac{1}{3} )=\cot .{{\cot }^{-1}}\frac{1}{3}=\frac{1}{3} $ .
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