Inverse Trigonometric Functions Question 189
Question: $ {{\tan }^{-1}}1+{{\tan }^{-1}}2+{{\tan }^{-1}}3= $
Options:
A) $ \frac{\pi }{2} $
B) $ \frac{\pi }{4} $
C) 0
D) None of these
Show Answer
Answer:
Correct Answer: D
Solution:
$ {{\tan }^{-1}}1+{{\tan }^{-1}}2+{{\tan }^{-1}}3 $
$ ={{\tan }^{-1}}1+\pi +{{\tan }^{-1}}( \frac{5}{-5} ) $
$ ={{\tan }^{-1}}1+\pi -{{\tan }^{-1}}1=\pi $ .
BETA
