A) $ \pi $
B) $ \frac{\pi }{2} $
C) 1
D) 0
Correct Answer: B
$ {{\cos }^{-1}}\sqrt{1-x}+{{\sin }^{-1}}\sqrt{1-x}={{\cos }^{-1}}\sqrt{x}+{{\sin }^{-1}}\sqrt{x}=\frac{\pi }{2} $
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