Inverse Trigonometric Functions Question 198

Question: $ {{\cos }^{-1}}\sqrt{1-x}+{{\sin }^{-1}}\sqrt{1-x}= $

Options:

A) $ \pi $

B) $ \frac{\pi }{2} $

C) 1

D) 0

Show Answer

Answer:

Correct Answer: B

Solution:

$ {{\cos }^{-1}}\sqrt{1-x}+{{\sin }^{-1}}\sqrt{1-x}={{\sin }^{-1}}\sqrt{x}+{{\cos }^{-1}}\sqrt{x}=\frac{\pi }{2} $ .