Inverse Trigonometric Functions Question 198
Question: $ {{\cos }^{-1}}\sqrt{1-x}+{{\sin }^{-1}}\sqrt{1-x}= $
Options:
A) $ \pi $
B) $ \frac{\pi }{2} $
C) 1
D) 0
Show Answer
Answer:
Correct Answer: B
Solution:
$ {{\cos }^{-1}}\sqrt{1-x}+{{\sin }^{-1}}\sqrt{1-x}={{\sin }^{-1}}\sqrt{x}+{{\cos }^{-1}}\sqrt{x}=\frac{\pi }{2} $ .