Inverse Trigonometric Functions Question 204
Question: $ 2{{\sin }^{-1}}\frac{3}{5}+{{\cos }^{-1}}\frac{24}{25}= $
Options:
A) $ \frac{\pi }{2} $
B) $ \frac{2\pi }{3} $
C) $ \frac{5\pi }{3} $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ 2{{\sin }^{-1}}\frac{3}{5}+{{\cos }^{-1}}\frac{24}{25}={{\sin }^{-1}}2\times \frac{3}{5}\sqrt{1-\frac{9}{25}}+{{\cos }^{-1}}\frac{24}{25} $
$ ={{\sin }^{-1}}\frac{24}{25}+{{\cos }^{-1}}\frac{24}{25}=\frac{\pi }{2} $ .
BETA
