Inverse Trigonometric Functions Question 208
Question: The principal value of $ {{\sin }^{-1}}
[ \sin ( \frac{2\pi }{3} ) ] $ is [IIT 1986]
Options:
A) $ -\frac{2\pi }{3} $
B) $ \frac{2\pi }{3} $
C) $ \frac{4\pi }{3} $
D) None of these
Show Answer
Answer:
Correct Answer: D
Solution:
The principal value of $ {{\sin }^{-1}}[ \sin ( \pi -\frac{2\pi }{3} ) ] $
$ ={{\sin }^{-1}}\sin ( \frac{\pi }{3} )=\frac{\pi }{3} $ .
BETA
