Inverse Trigonometric Functions Question 226
Question: $ {{\tan }^{-1}}\frac{1}{2}+{{\tan }^{-1}}\frac{1}{3} $ =
[MP PET 1997, 2003; UPSEAT 2000; Karnataka CET 2001; Pb. CET 2004]
Options:
A) 0
B) $ \pi /4 $
C) $ \pi /2 $
D) $ \pi $
Show Answer
Answer:
Correct Answer: B
Solution:
$ {{\tan }^{-1}}\frac{1}{2}+{{\tan }^{-1}}\frac{1}{3}={{\tan }^{-1}}( \frac{\frac{1}{2}+\frac{1}{3}}{1-\frac{1}{2}\times \frac{1}{3}} ) $
$ ={{\tan }^{-1}}( \frac{5}{5} )={{\tan }^{-1}}1=\frac{\pi }{4} $ .
BETA
