Inverse Trigonometric Functions Question 240

Question: The value of $ {{\sin }^{-1}}( \frac{\sqrt{3}}{2} )-{{\sin }^{-1}}( \frac{1}{2} ) $ is

[MP PET 2003]

Options:

A) $ 45^{o} $

B) $ 90^{o} $

C) $ 15^{o} $

D) $ 30^{o} $

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Answer:

Correct Answer: D

Solution:

$ {{\sin }^{-1}}[ \frac{\sqrt{3}}{2} ]-{{\sin }^{-1}}[ \frac{1}{2} ]=60^{o}-30^{o}=30^{o} $ .