Inverse Trigonometric Functions Question 242
Question: $ {{\cot }^{-1}}3+cose{c^{-1}}\sqrt{5} $ =
Options:
A) $ \frac{\pi }{3} $
B) $ \frac{\pi }{4} $
C) $ \frac{\pi }{6} $
D) $ \frac{\pi }{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ {{\cot }^{-1}}3+cose{c^{-1}}\sqrt{5}={{\cot }^{-1}}3+{{\cot }^{-1}}2 $
$ ={{\cot }^{-1}}( \frac{3\times 2-1}{3+2} )={{\cot }^{-1}}(1)=\frac{\pi }{4} $ .
BETA
